Prepare for the essential 636 Period 3 Motor Final Test with comprehensive flashcards and detailed questions. Access explanations and hints for each question to ace your exam!

Multiple Choice

What is the turns ratio Ns/Np given Ns = 40 and Np = 90?

Turns ratio is found by dividing the number of turns on the secondary by the number of turns on the primary. With Ns = 40 and Np = 90, you compute 40/90 = 0.444..., which rounds to 0.44. Since the secondary has fewer turns than the primary, the ratio is less than 1, indicating a step-down relationship. So the turns ratio Ns/Np is about 0.44.

Turns ratio is found by dividing the number of turns on the secondary by the number of turns on the primary. With Ns = 40 and Np = 90, you compute 40/90 = 0.444..., which rounds to 0.44. Since the secondary has fewer turns than the primary, the ratio is less than 1, indicating a step-down relationship. So the turns ratio Ns/Np is about 0.44.